Bash is abnormal in Makefile!

Question

all,

I have found that the same Makefile works well in Mac OS X, but does not work in Ubuntu. The snippet is as following:

start:
    @echo $(seperator)
    @if [[ "$(PROJECT)" == "" ]]; then \
         echo " Project powered by CodeMate!"; \
     else \
         echo "  $(PROJECT)"; \
     fi
    @echo $(seperator)

and make complains:

/bin/sh: [[: not found

Any idea?

Cheers,

Li

Updates:

I have changed the above conditional Bash statements to:

if test "$(PROJECT)" = ""; then \

then things work fine. So what is wrong with "[["?

Same goes for `printf %q`, dash has a builtin that does not support `%q`. — Doncho Gunchev, Jul 04 '23 at 12:45

score 10 · Answer 1 · edited May 20 '15 at 08:47

10

Place this at the top of your Makefile:

SHELL := /bin/bash # Use bash syntax

This happens because [[ is a builtin command of bash and you're running it with sh. The above line will set bash as default interpreter for the commands ran on makefile.

edited May 20 '15 at 08:47

0x2b3bfa0

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answered May 19 '15 at 14:53

Robin Winslow

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score 7 · Accepted Answer · answered Jan 14 '12 at 13:20

7

Makefiles use sh by default, not bash.

In Ubuntu sh point to dash, a POSIX compliant and minimalistic shell, not providing the [[ keywork.

answered Jan 14 '12 at 13:20

enzotib

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So we should limit the scripts in the Makefile. Thanks! – Li Dong Jan 14 '12 at 15:09

Bash is abnormal in Makefile!

2 Answers2

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