How insert variable inside quotes in this script?
f=`sed -n '1p' < /path/ls.txt`
I try something like this but it don't work..
f=`sed -n '"$i1"p' < /path/ls.txt`
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No, i try adivce from this post and it not help me. I want incrase variable `$i` to take {1, 2, .. x} line from .txt file – mechmati Jul 14 '21 at 08:53
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You *didn't* try the solution from there, you tried something else. Compare your usage of quotes with that in the answer there. – muru Jul 14 '21 at 08:54
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`sed -n "$i"'p' < /raid/path/ls.txt` now it work, thanks! – mechmati Jul 14 '21 at 09:48