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I want to create a script that change a username. I want to check if the user is not a system user. My idea is to check /etc/passwd and pick only users with an ID between 1000 and 60000 and users that have a /home directory like 

user:x:1005:1021::/home/user:/bin/sh

My grep command for now is like 

egrep -E '1[0-9]{3}.*/home' /etc/passwd

As you can see, it doesn't match my [1000-60000] pattern nor the name

wjandrea
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danaso
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    Minor point: `grep -E` is the same thing as `egrep`. There's no point in using both (`egrep -E`), just use `grep -E`. – terdon Jul 17 '19 at 14:47

1 Answers1

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You can use awk to find local users with id >= 1000:

awk -F: '$3>=1000 && $3!=65534 {print $1}' /etc/passwd

To also check for a home folder below /home:

awk -F: '$3>=1000 && $3 != 65534 && $6 ~ /^\/home/ {print $1}' /etc/passwd

Replace /etc/passwd with <(getent passwd) to list all users including network accounts ...

See also this related question, as well as this one.

pLumo
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